Optimal. Leaf size=319 \[ \frac {5 (-5 B+i A)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (\cot (c+d x)+i)}-\frac {\left (\frac {1}{32}-\frac {i}{32}\right ) ((7+2 i) A+(2+23 i) B) \log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {1}{32}-\frac {i}{32}\right ) ((7+2 i) A+(2+23 i) B) \log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}-\frac {\left (\frac {1}{16}-\frac {i}{16}\right ) ((2+7 i) A-(23+2 i) B) \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {((9+5 i) A-(25-21 i) B) \tan ^{-1}\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{16 \sqrt {2} a^2 d}+\frac {-B+i A}{4 d \sqrt {\cot (c+d x)} (a \cot (c+d x)+i a)^2} \]
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Rubi [A] time = 0.68, antiderivative size = 319, normalized size of antiderivative = 1.00, number of steps used = 14, number of rules used = 10, integrand size = 36, \(\frac {\text {number of rules}}{\text {integrand size}}\) = 0.278, Rules used = {3581, 3596, 3529, 3534, 1168, 1162, 617, 204, 1165, 628} \[ \frac {5 (-5 B+i A)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (\cot (c+d x)+i)}-\frac {\left (\frac {1}{32}-\frac {i}{32}\right ) ((7+2 i) A+(2+23 i) B) \log \left (\cot (c+d x)-\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}+\frac {\left (\frac {1}{32}-\frac {i}{32}\right ) ((7+2 i) A+(2+23 i) B) \log \left (\cot (c+d x)+\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{\sqrt {2} a^2 d}-\frac {\left (\frac {1}{16}-\frac {i}{16}\right ) ((2+7 i) A-(23+2 i) B) \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{\sqrt {2} a^2 d}+\frac {((9+5 i) A-(25-21 i) B) \tan ^{-1}\left (\sqrt {2} \sqrt {\cot (c+d x)}+1\right )}{16 \sqrt {2} a^2 d}+\frac {-B+i A}{4 d \sqrt {\cot (c+d x)} (a \cot (c+d x)+i a)^2} \]
Antiderivative was successfully verified.
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Rule 204
Rule 617
Rule 628
Rule 1162
Rule 1165
Rule 1168
Rule 3529
Rule 3534
Rule 3581
Rule 3596
Rubi steps
\begin {align*} \int \frac {A+B \tan (c+d x)}{\cot ^{\frac {5}{2}}(c+d x) (a+i a \tan (c+d x))^2} \, dx &=\int \frac {B+A \cot (c+d x)}{\cot ^{\frac {3}{2}}(c+d x) (i a+a \cot (c+d x))^2} \, dx\\ &=\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {\int \frac {-\frac {1}{2} a (A+9 i B)-\frac {5}{2} a (i A-B) \cot (c+d x)}{\cot ^{\frac {3}{2}}(c+d x) (i a+a \cot (c+d x))} \, dx}{4 a^2}\\ &=\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {\int \frac {\frac {5}{2} a^2 (i A-5 B)-\frac {3}{2} a^2 (3 A+7 i B) \cot (c+d x)}{\cot ^{\frac {3}{2}}(c+d x)} \, dx}{8 a^4}\\ &=\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {\int \frac {-\frac {3}{2} a^2 (3 A+7 i B)-\frac {5}{2} a^2 (i A-5 B) \cot (c+d x)}{\sqrt {\cot (c+d x)}} \, dx}{8 a^4}\\ &=\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {\operatorname {Subst}\left (\int \frac {\frac {3}{2} a^2 (3 A+7 i B)+\frac {5}{2} a^2 (i A-5 B) x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{4 a^4 d}\\ &=\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {((9+5 i) A-(25-21 i) B) \operatorname {Subst}\left (\int \frac {1+x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{16 a^2 d}+\frac {((9-5 i) A+(25+21 i) B) \operatorname {Subst}\left (\int \frac {1-x^2}{1+x^4} \, dx,x,\sqrt {\cot (c+d x)}\right )}{16 a^2 d}\\ &=\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}+\frac {((9+5 i) A-(25-21 i) B) \operatorname {Subst}\left (\int \frac {1}{1-\sqrt {2} x+x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{32 a^2 d}+\frac {((9+5 i) A-(25-21 i) B) \operatorname {Subst}\left (\int \frac {1}{1+\sqrt {2} x+x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{32 a^2 d}-\frac {((9-5 i) A+(25+21 i) B) \operatorname {Subst}\left (\int \frac {\sqrt {2}+2 x}{-1-\sqrt {2} x-x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{32 \sqrt {2} a^2 d}-\frac {((9-5 i) A+(25+21 i) B) \operatorname {Subst}\left (\int \frac {\sqrt {2}-2 x}{-1+\sqrt {2} x-x^2} \, dx,x,\sqrt {\cot (c+d x)}\right )}{32 \sqrt {2} a^2 d}\\ &=\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac {((9-5 i) A+(25+21 i) B) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt {2} a^2 d}+\frac {((9-5 i) A+(25+21 i) B) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt {2} a^2 d}+\frac {((9+5 i) A-(25-21 i) B) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{16 \sqrt {2} a^2 d}-\frac {((9+5 i) A-(25-21 i) B) \operatorname {Subst}\left (\int \frac {1}{-1-x^2} \, dx,x,1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{16 \sqrt {2} a^2 d}\\ &=-\frac {((9+5 i) A-(25-21 i) B) \tan ^{-1}\left (1-\sqrt {2} \sqrt {\cot (c+d x)}\right )}{16 \sqrt {2} a^2 d}+\frac {((9+5 i) A-(25-21 i) B) \tan ^{-1}\left (1+\sqrt {2} \sqrt {\cot (c+d x)}\right )}{16 \sqrt {2} a^2 d}+\frac {5 (i A-5 B)}{8 a^2 d \sqrt {\cot (c+d x)}}+\frac {3 A+7 i B}{8 a^2 d \sqrt {\cot (c+d x)} (i+\cot (c+d x))}+\frac {i A-B}{4 d \sqrt {\cot (c+d x)} (i a+a \cot (c+d x))^2}-\frac {((9-5 i) A+(25+21 i) B) \log \left (1-\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt {2} a^2 d}+\frac {((9-5 i) A+(25+21 i) B) \log \left (1+\sqrt {2} \sqrt {\cot (c+d x)}+\cot (c+d x)\right )}{32 \sqrt {2} a^2 d}\\ \end {align*}
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Mathematica [A] time = 3.13, size = 249, normalized size = 0.78 \[ \frac {\sec (c+d x) (\cos (d x)+i \sin (d x))^2 (A+B \tan (c+d x)) \left (2 (\sin (2 d x)+i \cos (2 d x)) ((-43 B+7 i A) \sin (2 (c+d x))+(5 A+41 i B) \cos (2 (c+d x))+5 A+9 i B)+(-\sin (2 c)+i \cos (2 c)) \sqrt {\sin (2 (c+d x))} \csc (c+d x) \left (((5-9 i) A+(21+25 i) B) \sin ^{-1}(\cos (c+d x)-\sin (c+d x))-(1+i) ((7+2 i) A+(2+23 i) B) \log \left (\sin (c+d x)+\sqrt {\sin (2 (c+d x))}+\cos (c+d x)\right )\right )\right )}{32 d \sqrt {\cot (c+d x)} (a+i a \tan (c+d x))^2 (A \cos (c+d x)+B \sin (c+d x))} \]
Antiderivative was successfully verified.
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fricas [B] time = 1.01, size = 763, normalized size = 2.39 \[ \frac {2 \, {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {i \, A^{2} + 2 \, A B - i \, B^{2}}{a^{4} d^{2}}} \log \left (\frac {{\left ({\left (8 i \, a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - 8 i \, a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {i \, A^{2} + 2 \, A B - i \, B^{2}}{a^{4} d^{2}}} - 8 \, {\left (A - i \, B\right )} e^{\left (2 i \, d x + 2 i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{4 \, {\left (i \, A + B\right )}}\right ) - 2 \, {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {i \, A^{2} + 2 \, A B - i \, B^{2}}{a^{4} d^{2}}} \log \left (\frac {{\left ({\left (-8 i \, a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} + 8 i \, a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {i \, A^{2} + 2 \, A B - i \, B^{2}}{a^{4} d^{2}}} - 8 \, {\left (A - i \, B\right )} e^{\left (2 i \, d x + 2 i \, c\right )}\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{4 \, {\left (i \, A + B\right )}}\right ) + {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {-49 i \, A^{2} + 322 \, A B + 529 i \, B^{2}}{a^{4} d^{2}}} \log \left (\frac {{\left ({\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {-49 i \, A^{2} + 322 \, A B + 529 i \, B^{2}}{a^{4} d^{2}}} + 7 i \, A - 23 \, B\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{8 \, a^{2} d}\right ) - {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )} \sqrt {\frac {-49 i \, A^{2} + 322 \, A B + 529 i \, B^{2}}{a^{4} d^{2}}} \log \left (-\frac {{\left ({\left (a^{2} d e^{\left (2 i \, d x + 2 i \, c\right )} - a^{2} d\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}} \sqrt {\frac {-49 i \, A^{2} + 322 \, A B + 529 i \, B^{2}}{a^{4} d^{2}}} - 7 i \, A + 23 \, B\right )} e^{\left (-2 i \, d x - 2 i \, c\right )}}{8 \, a^{2} d}\right ) + 2 \, {\left (6 \, {\left (A + 7 i \, B\right )} e^{\left (6 i \, d x + 6 i \, c\right )} - {\left (A + 33 i \, B\right )} e^{\left (4 i \, d x + 4 i \, c\right )} - 2 \, {\left (3 \, A + 5 i \, B\right )} e^{\left (2 i \, d x + 2 i \, c\right )} + A + i \, B\right )} \sqrt {\frac {i \, e^{\left (2 i \, d x + 2 i \, c\right )} + i}{e^{\left (2 i \, d x + 2 i \, c\right )} - 1}}}{32 \, {\left (a^{2} d e^{\left (6 i \, d x + 6 i \, c\right )} + a^{2} d e^{\left (4 i \, d x + 4 i \, c\right )}\right )}} \]
Verification of antiderivative is not currently implemented for this CAS.
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giac [F] time = 0.00, size = 0, normalized size = 0.00 \[ \int \frac {B \tan \left (d x + c\right ) + A}{{\left (i \, a \tan \left (d x + c\right ) + a\right )}^{2} \cot \left (d x + c\right )^{\frac {5}{2}}}\,{d x} \]
Verification of antiderivative is not currently implemented for this CAS.
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maple [C] time = 2.03, size = 5063, normalized size = 15.87 \[ \text {output too large to display} \]
Verification of antiderivative is not currently implemented for this CAS.
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maxima [F(-2)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Exception raised: RuntimeError} \]
Verification of antiderivative is not currently implemented for this CAS.
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mupad [F] time = 0.00, size = -1, normalized size = -0.00 \[ \int \frac {A+B\,\mathrm {tan}\left (c+d\,x\right )}{{\mathrm {cot}\left (c+d\,x\right )}^{5/2}\,{\left (a+a\,\mathrm {tan}\left (c+d\,x\right )\,1{}\mathrm {i}\right )}^2} \,d x \]
Verification of antiderivative is not currently implemented for this CAS.
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sympy [F(-1)] time = 0.00, size = 0, normalized size = 0.00 \[ \text {Timed out} \]
Verification of antiderivative is not currently implemented for this CAS.
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